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1.8x^2-3.8x+5=10
We move all terms to the left:
1.8x^2-3.8x+5-(10)=0
We add all the numbers together, and all the variables
1.8x^2-3.8x-5=0
a = 1.8; b = -3.8; c = -5;
Δ = b2-4ac
Δ = -3.82-4·1.8·(-5)
Δ = 50.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.8)-\sqrt{50.44}}{2*1.8}=\frac{3.8-\sqrt{50.44}}{3.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.8)+\sqrt{50.44}}{2*1.8}=\frac{3.8+\sqrt{50.44}}{3.6} $
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